Question

the sum of the numinator and the denominater of a fraction is 4 more then twive the numintar if 3 is add to each of numerater and denominater their ratio becomes 2:3 find the fractions

Answer 1

Answer:

Let's take

• Numerator be X
• denominator be Y

$fraction \: = \frac{x}{y}$

According to the first condition

• ⇒x+y=2x+4
• ⇒y=x+4..eq1

According to the second condition

$\frac{x + 3}{y + 3} = \frac{2}{3}$

• ⇒3x+9=2y+6
• ⇒3x−2y=−3..eq2

Substitute the value of y from eq1 to eq2

• ⇒3x−2(x+4)=−3
• ⇒3x−2x+8=−3
• ⇒x=5

Put x=5 in eq1

• ⇒y=5+4
• ⇒y=9

$hence \: th e\: fraction \: = \frac{5}{9}$

Thnku !

Answer 2

Answer:

Let's take

Numerator be X

denominator be Y

fraction \: = \frac{x}{y} fraction=

y

x

According to the first condition

⇒x+y=2x+4

⇒y=x+4..eq1

According to the second condition

\frac{x + 3}{y + 3} = \frac{2}{3}

y+3

x+3

=

3

2

⇒3x+9=2y+6

⇒3x−2y=−3..eq2

Substitute the value of y from eq1 to eq2

⇒3x−2(x+4)=−3

⇒3x−2x+8=−3

⇒x=5

Put x=5 in eq1

⇒y=5+4

⇒y=9

hence \: th e\: fraction \: = \frac{5}{9} hencethefraction=

9

5

Step-by-step explanation:

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