Math, asked by sriku2829, 1 year ago

The sum of the one-eighth,one-twelfth and one-twentieth parts is 31,find the number

Answers

Answered by manikiran18
41

HLO MATE

Let the no. be x...

Then,

x/8 + x/12 + x/20 = 31

So,

(15x + 10x + 6x)/120 = 31

So,

31x/120 = 31

Hence,

x = 31 * 120/31

= 120.

MARK AS BRAINLIEST

Answered by abhi569
41

Answer:

Required number is 120.

Step-by-step explanation:

Let the required number be a.

Given,

Sum of one-eighth,one-twelfth and one-twentieth parts is 31.

= > one eighth of a + one-twelfth of a + one-twentieth of a = 31

= > 1 / 8 of a + 1 / 12 of a + 1 / 20 of a = 31

= > a[ 1 / 8 + 1 / 12 + 1 / 20 ] = 31

= > a[ ( 15 + 10 + 6 ) / 120 ] = 31

= > a ( 31 / 120 ) = 31

= > a( 1 / 120 ) = 1

= > a = 120

Hence the required number is 120.

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