The sum of the one-eighth,one-twelfth and one-twentieth parts is 31,find the number
Answers
Answered by
41
HLO MATE
Let the no. be x...
Then,
x/8 + x/12 + x/20 = 31
So,
(15x + 10x + 6x)/120 = 31
So,
31x/120 = 31
Hence,
x = 31 * 120/31
= 120.
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Answered by
41
Answer:
Required number is 120.
Step-by-step explanation:
Let the required number be a.
Given,
Sum of one-eighth,one-twelfth and one-twentieth parts is 31.
= > one eighth of a + one-twelfth of a + one-twentieth of a = 31
= > 1 / 8 of a + 1 / 12 of a + 1 / 20 of a = 31
= > a[ 1 / 8 + 1 / 12 + 1 / 20 ] = 31
= > a[ ( 15 + 10 + 6 ) / 120 ] = 31
= > a ( 31 / 120 ) = 31
= > a( 1 / 120 ) = 1
= > a = 120
Hence the required number is 120.
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