Question

The sum of the oxidation numbers of all the carbons in c6h5cho

Answer 1

Heya....✋

Oxidation state of C in C6H5CHO is

6x+5+x+1+(-2)=0
7x+6-2=0
7x+4=0
7x=-4
x=-4/7

hope it helps
mark....

Answer 2

The sum of oxidation numbers of all the carbons in $C_6H_5CHO$ is $-\frac{4}{7}$.

Explanation:

The name of $C_6H_5CHO$ is Benzaldehyde which consists of an aldehyde attached to the ring of the benzene. Its molecular mass is 106 grams.

It is mainly used in manufacturing cosmetics, pharmaceuticals, and soaps.

In $C_6H_5CHO$, there will be bonds between five carbon-hydrogen bonds and a single bond between carbon-aldehyde and there are 7 carbon-carbon bonds.

When we have carbon-hydrogen bond, the oxidation state of carbon is -1 and when we have carbon-carbon bond it is 0 and when we have carbon-aldehyde bond it is 1.

So, by multiplying the no. of bonds of each type and adding all those will result in the sum of oxidation states of carbon in $C_6H_5CHO.$

Therefore,

6x+5+x+1+(-2)=0

7x+6-2=0

7x+4=0

7x=-4

x=-4/7.

Learn more about oxidation numbers

What are the oxidation numbers of the underlined elements in each of the following and how do you rationalise your results?

https://brainly.in/question/2161394

What is oxidation number of iodine in NaIO3

https://brainly.in/question/3540995