The sum of the oxidation numbers of both the nitrogen atoms in NH4NO3 is :
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The oxidation of nitrogen in NH4+ is -3. The hydrogen atoms have +1 and there are four of them. And net charge on the molecule is +1. Let nitrogen's oxidation state be x. Therefore, (4×(+1)) + x = +1. Hence, x is -3.
The oxidation number nitrogen of NO3- is +5. The oxygen atoms have -× and there are 3 of them. And net charge on the molecule is -1. Let the oxidation state of nitrogen be x. Therefore, (3×(-2)) + x = -1. Hence, x = +5.
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