Question

The sum of the parallel sides of a trapezium is 25 cm and its area is 150 cm square.find its altitude.

Answer 1

The altitude of the trapezium is 12 cm.

Step-by-step explanation:

The area of a trapezoid is given by  

$A = \frac{1}{2} \times(\textrm {Sum of it's parallel side lengths}) \times \textrm {Altitude}$

Now, it is given that the sum of the parallel sides lengths of the trapezium is 25 cm. and its area is 150 cm².

If the altitude of the trapezium is h, then we can write

$\frac{1}{2} \times (25) \times h = 150$

⇒ h = 12 cm.

Hence, the altitude of the trapezium is 12 cm. (Answer)

Answer 2

Given: The sum of the parallel sides of a trapezium is $25\ cm$ and its area is $150\ cm^{2}$

To Find: What its altitude.

Step-by-step explanation:

We know,

Area of trapezium is given,

                                           $=\frac{a+b}{2}\times h$ Where, $a\ and\ b$ are the parallel sides.

                                                                          $h$ is altitude.

Here in the question is given sum of the parallel sides of a trapezium is $25\ cm$

So, $(a+b)=25$

And Area of the trapezium is $150\ cm^{2}$

Therefore,

  $150=\frac{25}{2}\times h$

⇒$25\times h=300$

⇒$h=\frac{300}{25}$

∴ $h=12$ cm

So, The Altitude is $12\ cm$.