Question

the sum of the perimeter of two rectangle 16 cm*12 cm and 20 cm * 15 CM size is equal to the perimeter of a largest square find the side and the area of the square

Answer 1

Here,l=16 b=12 and h =15cm

the sum of the perimeter of two rectangle=2×(lb+bh+hl)

=2×(16×12+12×15+15×16)

=2×(192+180+240)

=2× 612

= 1224 cm2

now,for the square,

the side of largest square AB=BC=CD=AD=15cm

now,the perimeter of largest square=15

=> 4a =15

a=15/4

a=3.75cm

area of the square=side ×side

=3.75×3.75 cm2

=14.0625cm2 or 15centimeter square (approx)

so the sum of the perimeter of two rectangle =1224 cm2

the side of the square=3.75 cm

and the area of the square=14.0625 cm2