Question

The sum of the perimeter of two square is 76 and the difference between their areas is 57 ?what is the difference between the perimeters of the square?
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Answer 1

Answer:

and their difference between their area is 57 a) if their lenghth of sides of the square is x unit. what will be the perimeter . 2.

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Answer 2

Answer:

difference between the perimeter of squares =12

Step-by-step explanation:

we know that area of square=a^2;( a is side of square)

perimeter of square =4a

let side of 1st square=x

let side of second square=y

given difference of area of squares= x^2-y^2=57

sum of perimeter of squares=4x+4y=76

=4(x+y)=76

x+y=76/4

x+y=19

formula of (a^2-b^2)=(a+b)(a-b)

x^2-y^2=57

(x+y)(x-y)=57

(19)(x-y)=57

(x-y)=57/19

(x-y)=3

multiplying 4 on both sides

4(x-y)=4(3)

4x-4y=12

difference of perimeter of squares= 4x-4y

So, answer is 12