Question

The sum of the perimeters of two squares is 80 and the difference between their areas is 160. What is the difference between the perimeters of the square?

Answer 1

Answer:

Step-by-step explanation:

4x+4y=80

x+y=20

x=20-y.......(1)

now,

x²-y²=160

(20-y)²-y²=160

400-40y+y²-y²²=160

400-160=40y

40y=240

y=6

then,

x=20-y

x=20-6

x=14

now,

Difference between the perimeter=x-y

=14-6

=8