Question

the sum of the perimeters of two squares of sides 18 CM and 12cm respectively, is equal to the perimeter of a rectangle. if the length of a rectangle is 36cm what should be the breadth of the rectangle? which is greater the sum of the areas of the two squares or the area of the rectangle and how much?

Answer 1

it will help u out !!!!!!!

Answer 2

Perimeter of square I = 4a
                                   = 4(18)
                                   = 72 cm
Perimeter of square II = 4a
                                    = 4(12)
                                    = 48 cm
Acc to question,
Perimeter of 2 squares = Perimeter of rectangle
                        72 + 48 = 2(36 + b)
                           120/2 = 36 + b
                                  b = 60 - 36
                                  b = 24 cm
Area of square I = a²
                           = (18)²
                           = 324 cm²
Area of square II = a²
                            = (12)²
                            = 144 cm²
Sum of Areas of squares = 324+144
                                         = 468 cm²
Area of rectangle = lb
                             = (36)(24)
                             = 864 cm²
Hence area of rectangle is greater than that of sum of areas of squares
They differ by = 864-468
                       = 396 cm²

:) Hope this helps!!!