Question

the sum of the present age of a father and a son is 54 years.six years ago the father's age was 2 more than 4 times the age of the son at that time.find their present age

Answer 1

Answer:

1. let age of father be x and that of son be y years respectively
2. so x+y=54
3. father's age six years ago =(x-6)

and son's age six years ago =(y-6)

4. so (x-6) =4×(y-6) + 2

x-6 = 4y-24+2

x-6 = 4y-22

x = 4y-16

5. using equation 4 in equation 2

4y-16+y=54

5y=70

so y = 14 years= son's age

and x + 14=54

x = 40years =father's age