Math, asked by anil177, 1 year ago

the sum of the present age of a father and a son is 92 years . ten years ago the product of their ages in years was 1100 find their present ages

Answers

Answered by Sneha3123
6
Heya mate,
Here is your answer,

Let 10yrs. ago,
Son's age = x

then according to the question,
son's age × father's age = 1100
→ x × father's age = 1100
→ father's age = 1100/x

So, present age,
of son = x + 10 yrs.
of father = 1100/x + 10

according to the question,

1100/x + 10 + x = 92
→ 1100/x + x = 92 - 10
→ 1100/x +x = 82
→ 1100 + x = 82 × x
→ 1100 = 82x - x
→ 1100 = 81x
→ 81x = 1100
→ x = 1100/81
= 13.58 yrs.


Hence, Son's present age = 13.58 yrs. and
father's present age = 1100/13.58 = 81 yrs.


I had tried to solve it in the simplest form.

Hope this helps

if you have further doubt or want any help, feel free to ask me. I would like and try to help you.

Thank you

#Sneha
☆ brainly benefactor ☆

anil177: the answer is wrong
Similar questions