The sum of the present age of the father and son is 54 years. 5 years ago.
the age of the father was 3 times that of the son. Find their present age?
1.
Answers
Answer:
present age of father = 38 years
present age of son = 16 years
Step-by-step explanation:
let the present age of father = x
and present age of son = y
A.T.Q
x + y = 54 -------(1)
(x - 5) = 3(y - 5)
x - 5 = 3y - 15
x - 3y = -15 + 5
x - 3y = -10 -----(2)
on subtract eq 1 and 2
x + y = 54
x - 3y = -10
- + +
4y = 64
y = 64/4
y = 16
put y in eq 1
x + y = 54
x + 16 = 54
x = 54 - 16
x = 38
let the present age of father be y
and present age of son be y.
by question,
x+y=54
x=54-y------------(1)
5 years ago
father's age was (x-5)yrs
son's age was (y-5)yrs
(x-5)=3(y-5)
x-5=3y-15
x-5=3(54-x)-15
x-5=162-3x-15
x+3x=147+5
4x=152
x=152/4
x=38
present age of father is 38 yrs
present age of son is (54-38)yrs=16 yrs.