Question

The sum of the present ages (in years) of a father and a son is 110. Ten years ago, the product of their ages (in years)
was 1856. Their present ages are to be found.

Plz Give me answer ,,,it is Urgent...​

Answer 1

Answer:

Step-by-step explanation:

let be the present ages be x,y

x+y=110

ten years ago ages be x-10,y-10

(x-10).(y-10)=xy-10x-10y+100=1856

xy-10(x+y)+100=1856

xy-1100+100=1856

xy=2856

x=110-y

(110-y).y=2856

110y-y^2=2856

by solving you get 62,48 are ages

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