Question

The sum of the present ages of a boy
and his father, is 48 years. If the age
of the father is seven times that of
his son, find their ages.​

Answer 1

Answer:

let boy's age be x

then,

father's age will be 7x

sum of their age =48

a/q

7x+x=48

8x=48

x=48/8

x=6

Answer 2

Answer:

The boy is 8 years old

Step-by-step explanation:

Let the age of boy be x and his father be 7x

Given

Age of father = 48

Atq

7x + 48 = x

7x - x = 48

6x = 48

x = 48/6

x= 8