Math, asked by miyarahmat595, 5 months ago

The sum of the present ages of a father and his son is 40 years. Four years hence
father will be three times as old as his son will be. Find their present ages.​

Answers

Answered by LogicSaves
1

Answer:

present age of son is 13 and father is 27

Step-by-step explanation:

let the present age of son be x and father be y

x+y=40

=> y=40-x ------(i)

after 4 years

y+4=3(x+4)

y+4=3x +12

from (i)-

40-x+4=3x+12

4x=52

x=13

y=40-13=27

present age of son is 13 and father is 27

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