The sum of the present ages of a father and his son is 60 years. five years ago, father's age was four times the age of the son. So now the son's age will be ?
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3
Answer:
Let the present ages of son and father be x and (60 -x) years respectively.
Then, (60 - x) - 5= 4(x - 5)
55 - x = 4x - 20
5x = 75
x = 15 yrs
Answered by
0
Let the age of the son be X, the age of father will be 60-x
Five years ago (x-5) and (55-x), father's age will be 4 times
= 4(x-5) = 55-x
= 4x - 20 = 55 - X
= 5x = 75
= x = 15
Hence, the son's present age is 15 years
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