Math, asked by twinsdylanf3, 10 months ago

The sum of the present ages of a father and his son is 60 years. five years ago, father's age was four times the age of the son. So now the son's age will be ?​

Answers

Answered by Anonymous
3

Answer:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 5= 4(x - 5)

55 - x = 4x - 20

5x = 75

x = 15 yrs

Answered by ratdna
0

Let the age of the son be X, the age of father will be 60-x

Five years ago (x-5) and (55-x), father's age will be 4 times

= 4(x-5) = 55-x

= 4x - 20 = 55 - X

= 5x = 75

= x = 15

Hence, the son's present age is 15 years

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