Math, asked by Abidkatalur3456, 1 year ago

The sum of the present ages of a father and his son is 70 years. Five years ago, father's age was 5 times the age of the son, so now the son's age will be?
A) 12
B) 14
C) 15
D) 19

Answers

Answered by yahootak
16
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Refer to the attachment.

\underline{\boxed{\boxed{Option\: c)15 \:years}}}

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hulra12345: nice answer
Answered by Rameshjangid
0

Answer:- The son's age now is = 15 years

Given in the question that:-

The sum of the present ages of a father and a son is given in the question = 70 years

Five years ago father's age was 5 times of the age of the son.

Solution is as follows:-

Let us assume that the father's present age is = y years and

Son's present age = x years

According to question,

x+y = 70       eq(1)

5 years ago,

Father's age was = y-5 years and

Son's age was = x-5 years

It is also said that 5 years ago,

Father's age was = 5 times the son's age

i.e.,                 y-5  = 5(x-5)

                     y-5   = 5x-25

                     y-5x  = -25+5

                    -(5x-y) = -20

                       5x-y = 20  (the minus in both sides will get cancelled) eq(2)

Now, by adding both the equations i.e., equation (1) and equation (2), we get

6x = 90

  x = 90/6

   x = 15

Therefore,

The present age of the son is = x years

                                                  = 15 years

If you want to find father's age also then simply subtract age of son from 70

Putting the value of x = 15 in the equation (1)

x+y = 70

15+y = 70

  y    = 70-15

   y   = 55

Therefore, the father's present age is = y years

                                                               = 55 years

To know more about the mentioned topic please go through the following links

Link1:- https://brainly.in/question/40897126?

Link2:- https://brainly.in/question/32221046?

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