Math, asked by rishabh49, 1 year ago

the sum of the present ages of a father and his son is 99 years. when the father was as old as his is now his age was four times the age of the son at that time. The ratio of the present ages of the son and the Father is ...


Aryav: 10,40
Aryav: son n father
rishabh49: no

Answers

Answered by throwdolbeau
9

Answer:

The ratio in the simplest form = 1 : 4

Step-by-step explanation:

Let the present age of father be x and the present age of his son be y

Now, sum of their ages is given to be 99

⇒ x + y = 99 ........(1)

Also, when the father was as old as his is now his age was four times the age of the son at that time

⇒ x = 4y

Putting this value in equation (1)

4y + y = 99

⇒ y ≈ 20

Therefore, x = 80

Ratio of the present ages of the son and the father = 20 : 80

Therefore, The ratio in the simplest form = 1 : 4

Answered by coolshubham828111
2

Answer=7:4

Step-by-step explanation:

Let present age of father and son is :X&Y

And assume n is the year passed

So according to the question

X-n=Y,n=X-Y

Also it is given that

X-n=4(Y-n)

X-n=4Y-4n

Putting value of n

X-X+Y=4Y-4X+4Y

4X=7Y

X:Y=7:4

Ans.

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