Question

The sum of the present ages of a woman and her daughter is 60 years. Six years ago, the woman’s age was five times the age of the daughter. How old is the woman now?

Answer 1

Solution

Given:-

• The sum of the present ages of a woman and her daughter is 60 years
• Six years ago, the woman’s age was five times the age of the daughter

Find:-

• Age of woman ?

Explanation

Let,

• Age of woman = x year
• Age of his daughter = y year

A/C to question

(The sum of the present ages of a woman and her daughter is 60 years )

==> x + y = 60 -------------Equ(1)

And,

(Six years ago, the woman’s age was five times the age of the daughter)

==> (x -6) = 5 × (y-6)

==> x - 5y = -30 + 6

==> x - 5y = -24 -----------Equ(2)

Subtract equ(1) & equ(2)

==> y + 5y = 60 + 24

==> 6y = 84

==> y = 84/6

==> y = 14

Keep value of y in equ(1)

==> x + 14 = 60

==> x = 60 - 14

==> x = 46

Thus

• Age of Woman (x) = 46 years
• Age of his daughter (y) = 14 years

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