The sum of the present ages of father and a son is 110years ten yeats ago the product of their ages in year was 1856 find their present age
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Father's present age = a
son's present age = b
a + b = 110
a = 110 - b .........(1)
10 years back
(a - 10) (b - 10) = 1856
(110 - b - 10) (b-10) = 1856
(100 - b) (b - 10) = 1856
100b - b² - 1000 + 10b = 1856
b² - 110b + 2856 = 0
b² - 48b - 62b + 2856 = 0
b(b - 48) - 62(b - 48) = 0
(b - 62) (b - 48) = 0
Their ages = 62, 48
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