Math, asked by saisubi76, 1 year ago

the sum of the present ages of father and son is 68 years. eight years ago, the ratio of their age was 12:1. what will be the ratio of their ages 4 years hence​

Answers

Answered by rithinv78
4

Answer:

15:4

Step-by-step explanation:

sum of father and son = 68

eight years ago ratio = 12:1

sum of ages eight years ago= 68-(8+8) = 68-16 = 52

13 units = 52

1 unit =4

so ages of father and son 8 years ago are 4*12 = 48 and 4*1 = 4

present age = 56 and 12

ages after 4 years = 60 and 16

ratio 60:16 = 30:8 = 15:4

hope it helps:)

Answered by sumit1281
1

Answer:

let the present age of father be x

Step-by-step explanation:

let the present age of his son be y

atq to the questions

x+y=68

in second conditions

8yrs ago

father age

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