the sum of the present ages of father and sum is 90 years.10 years earlier the ratio of their ages was 5:2.the present age of the father is
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Answered by
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let the present age of father be x and
sun be y
x+y=90 .... (given) (I)
10 years earlier
father's age =x-10
sun's age=y-10
x-10/y-10=5/2
2x-20=5y-50
5y-2x=30 .... (II)
multiply equation (I) by 2 we get,
2x+2y=180 ...... (III)
add equation (II) &(III) we get,
7y=210
y=30
x=90-30=60
age of sun is 30 and age of father is 60
sun be y
x+y=90 .... (given) (I)
10 years earlier
father's age =x-10
sun's age=y-10
x-10/y-10=5/2
2x-20=5y-50
5y-2x=30 .... (II)
multiply equation (I) by 2 we get,
2x+2y=180 ...... (III)
add equation (II) &(III) we get,
7y=210
y=30
x=90-30=60
age of sun is 30 and age of father is 60
Thatsomeone:
thanks for selecting my answer as brainliest
Answered by
0
Answer:
The present age of the father is 60
Step-by-step explanation:
From the above question,
Given:
sum of present age of father+ son= 90yrs
10yrs earlier age= 5:2
To find:
The present age of the father?
Solution:
Let their ages be x
So, 10yrs ago, their ages= 5x(father), 2x(son)
And after 10 years(according to the question), their age is
father= 5x+10
son= 2x+10
Also, (5x+10)+(2x+10)=90(present age)
5x+10+2x+10=90
7x+20= 90
7x= 90-20
x= 70/7
= 10
Therefore, the present age of the father will be;
5x+10
=5×10+10
= 60
#SPJ2
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