Question

The sum of the present ages of Hari and
Mohan is double of their difference. Four
years ago this ratio was one and half times.
Find the ratio of their ages after 12 yrs.
​

Answer 1

Step-by-step explanation:

the ratio after 12 years is 3:4

Answer 2

Hey Dear,

◆ Answer -

After 12 years,

Hari's age : Mohan's age = 9 : 5

● Explaination -

Let x & y be the present ages of Hari & Mohan.

Presently,

x + y = 2 (x-y)

x + y = 2x - 2y

x - 3y = 0

x = 3y ...(1)

4 years ago,

(x-4) + (y-4) = 1.5 [(x-4) - (y-4)]

x + y - 8 = 1.5x - 6 - 1.5y + 6

0.5x - 2.5y = -8

x - 5y = -16 ...(2)

Substitute x = 3y

3y - 5y = -16

-2y = -16

y = 8 yrs

Substituting y = 8,

x = 3×8

x = 24 yrs

After 12 years, ratio of their ages,

(x+12)/(y+12) = (24+12) / (8+12)

(x+12)/(y+12) = 36 / 20

(x+12)/(y+12) = 9/5

Therefore, ratio of their ages will be 9/5 after 12 years.

Hope this helped..