Question

the sum of the present ages of Manish and savita is 31. years 3 years ago Manish's age was four times Savita's age at that time. find their present ages.​

Answer 1

Answer:

Let, the age of Manish = a

age of Savita = b

Sum of their ages is 31 year:

→ a + b = 31

→ a = 31 - b ... (1)

3 years ago:

Manish's age = (a - 3) years

Savita's age = (b - 3) years

In question: that time

→ Manish = 4 * Savita

→ (a - 3) = 4(b - 3)

→ a - 3 = 4b - 12

→ a - 4b = - 12 + 3

→ (31 - b) - 4b = - 9 {a=31 - b}

→ 31 - 5b = - 9

→ 31 + 9 = 5b → 40 = 5b

→ (40/5) = b → b = 8

Putting the value of x in equation 1,

→ a = 31 - 8 = 23 year

Age of manish = a =23 years

Age of manish = a =23 yearsAge of savita = b = 8 years

Step-by-step explanation:

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Answer 2

Answer:

Savita's present age = 9 years

Manish's present age = 27 years

Step-by-step explanation:

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