Question

the sum of the present ages of mother and her daughter is 50 years .after 20 years mothers ag3 will be twice her daughter age at that time .find their present age​

Answer 1

Answer:

Let the mother's present age be 'x'

and daughter's present age be 'y'

According to the question,

x + y = 50 ........(i)

2x = y + 20...........(ii)

from the equation (ii),

2x - y = 20.........(iii)

{( i × 2 ) - ii}

$2x + 2y = 50 \\ - 2x + y = 20 \\ - - - - - - - \\ \: \: \: \: \: 3y = 30 \\ or \: \: y = 10$

y → (i)

$x + 10 = 50 \\ o r\: x = 50 - 10 \\ or \: x = 40$

So, mother's present age is 40 years

and her daughter's present age is 10 years.

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Answer 2

Step-by-step explanation:

▪️Let the parents age be 'x' and

▪️Let the daughter's age be 'y'

According to the question,

x + y = 50 ____(i)

2x = y + 20____(ii)

From the equation (ii) it can be said that,

2x - y = 20____(iii)

{( i×2) - iii}

$2x + 2y = 100 \\ -2x + y = -20 \\ </p><p> - - - - - - - - \\ </p><p> \: \: \: \: \: 3y = 80 \\ </p><p>or, y = \frac{80}{3}$

Daughter's present age is 80/3

So, mother's present age is ,

$x + \frac{80}{3} = 50 \\ </p><p>x = 50 - \frac{80}{3} \\ x = \frac{150 - 80}{3} \\ x = \frac{70}{3}$

$So, \: \: mother's \: \: present \: \: \\ age \: \: is \: \: \frac{70}{3} years.$

Age can't be in fraction or in minus (negative). So, I think something is wrong in ur question. Pls check your question.

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