Question

The sum of the present ages of son and father is 60 years . six years hence father's age will be twice his sons present age . then fathers present age is ?​

Answer 1

✬ Father's age = 38 years ✬

✬ Son's age = 22 years ✬

Explanation:

Given:

• Sun of father and son age is 60 years.
• After 6 years father age will be twice of son age.

To Find:

• What is the present age of father ?

Solution: Let the father's age be x and son's age be y years. Therefore,

➟ ( Father + son ) age = 60

➟ x + y = 60

➟ y = 60 – x.....(1)

[ Now, after 6 years ]

➨ Father's age = (x + 6) years

A/q

• After 6 years father age will be twice of son's present age.

$\implies{\rm }$ (x + 6) = 2y

$\implies{\rm }$ x + 6 = 2(60 – x)

$\implies{\rm }$ x + 6 = 120 – 2x

$\implies{\rm }$ x + 2x = 120 – 6

$\implies{\rm }$ 3x = 114

$\implies{\rm }$ x = 114/3

$\implies{\rm }$ x = 38

So, present ages of

➮ Father is x = 38 years

➮ Son age is y = 60 – 38 = 22 years

___________________

★ Verification ★

➩ 38 + 22 = 60

➩ 60 = 60

[ After 6 years ]

➩ (38 + 6) = 2(22)

➩ 44 = 2(22) Father is two times

➩ 44 = 44

$\large\boxed{\texttt{Verified}}$

Answer 2

Answer :-

Present age of father is 38 years.

Given :

• The sum of the present ages of the son and father is 60 years.
• 6 years hence, father's age will be twice of his son's present age.

To find :

• Present age of father.

Solution :

Consider,

• Present age of son = x years
• Present age of father= y years

According to the 1st condition :-

• The sum of present ages of the son and father is 60 years.

x + y = 60

→ x = 60-y .................(i)

According to the 2nd condition :-

• 6 years hence, father's age will be twice of his son's present age.

After 6 years ,

• Age of son = (x+6) years
• Age of father = (y+6) years

y + 6 = 2x

→ y + 6 = 2(60-y) [ Put x = 60-y]

→ y +6 = 120 -2y

→ y +2y = 120-6

→ 3y = 114

→ y = 38

★ Present age of father = 38 years.