Question

The sum of the present ages of three men is 108
years. Three years ago, the ratio of their ages was
10:11:12. Find the present age of each of them.​

Answer 1

Step-by-step explanation:

let the age of first person before 3 years be 10x

then the age of second person 3 years ago will be 11x

and for third person it will be 12x

at present age of first, second, third person will be 10x+3,11x+3,12x+3

now it is given

10x+3+11x+3+12x+3=108

33x=99

x=3

present age of first, second, third person is 33,36,39 years respectively

Answer 2

ACCORDING TO THE QUESTION ,
3 years ago ,
their ages were 10x , 11x and 12x.
After 3 years,
10x+3+11x+3+12x+3 = 108
= 33x+9= 108
= 33x = 108–9
= 33x= 99
= x=3
10x=10x3=30
11x=11x3=33
12x=12x3=36
Ans - The present ages of the three men are
30yrs, 33yrs and 36yrs.