The sum of the present ages of three men is 108 years. Three years agi the ratii of their ages was 10:11:12.Find the present age of each of them??
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Solution
Given:
The sum of there ages=108 years
Let
The age of 1st man= 10x
The age of 2nd man= 11x and
The age of 3rd man= 12x
Now, As per ques:
=10x+11x+12x=108 years
=33x= 108 years
= x = 108/33=3.2
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