Question

The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence?​

Answer 1

Answer:

Sum of ages of $A$ and $B$ after $5$ years is $70$ years.

Step-by-step explanation:

Given : The sum of the present ages of two persons A and B is 60.

                 $A+B=60$

           The age of A is twice that of B.

                 $A=2B$

To find : The sum of their ages 5 years hence?​

Solution :

• It is given that, the sum of the present ages of two persons A and B is 60.

                 $A+B=60$ .... (i)

           The age of A is twice that of B.

                 $A=2B$ .... (ii)

• Put value of A from (i) in (ii), we get

              $2B+B=60$

                 ∴ $3B=60$

                   ∴ $B=\frac{60}{3}$

                   ∴ $B=20$

• Put the value of B in equation (i), we get

                 $A+20=60$

                    ∴ $A=60-20$

                    ∴ $A=40$

• ∴ Present age of $A$ is $40$ years and $B$ is $20$ years.
• Now,

   Sum of their ages after $5$ years = $(40+5)+(20+5)$

                                                 = $45+25$

                                                 = $70$

• ∴  Sum of ages of $A$ and $B$ after $5$ years is $70$ years.

Answer 2

Step-by-step explanation:

The sum of the present ages of two persons A and B is 60. If the age of A is twice that of B, find the sum of their ages 5 years hence? 2B + B = 60 => B = 20 then A = 40. 5 years, their ages will be 45 and 25.