The sum of the reciprocal of focal distance of a focal chord of y2=4ax is
Answers
Answered by
1
Answer:
Let y2 = 4ax be the equation of a parabola and (at2, 2at) a point P on it. Suppose the coordinates of the other extremity Q of the focal chord through P are (at12, 2at1).
Then, PS and SQ, where S is the focus (a, 0), have the same slopes
⇒ (2at-0)/(at2- a) = (2at1 - 0)/(at12 - a)
⇒ tt12 – t = t1t2 – t1
⇒ (tt1 + 1) (t1 – t) = 0.
Hence t1 = –1/t, i.e. the point Q is (a/t2, –2a/t).
The extremities of a focal chord of the parabola y2 = 4ax may be taken as the points t and –1/t.
Step-by-step explanation:
Similar questions