the sum of the reciprocals of rahman's Ages 3 years ago and 5 years from now is 1/3 find the present age
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Sol.
Let the present age of Brahman is x .
so,
1/x+5 +1/x-3 = 1/3
x-3+x+5/x^2+2x-15 = 1/3
(2x+2)3 = x^2+2x-15
6x+6 = x^2+2x -15
x^2-4x-21 =0
by solving this quadratic equation, we get
x^2 +3x -7x - 21 = 0
x(x + 3) - 7( x +3) =0
(x-7)(x+3) =0
so,. x-7 =0. and x+3=0
x = 7 and -3
so the age of rahman is 7 yrs.
Let the present age of Brahman is x .
so,
1/x+5 +1/x-3 = 1/3
x-3+x+5/x^2+2x-15 = 1/3
(2x+2)3 = x^2+2x-15
6x+6 = x^2+2x -15
x^2-4x-21 =0
by solving this quadratic equation, we get
x^2 +3x -7x - 21 = 0
x(x + 3) - 7( x +3) =0
(x-7)(x+3) =0
so,. x-7 =0. and x+3=0
x = 7 and -3
so the age of rahman is 7 yrs.
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