Math, asked by Mister360, 2 months ago

The sum of the reciprocals of Rehman’s ages, (in years) 3 years ago and 5 years from now is 1/3. Find their present age
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Answers

Answered by amankumaraman11
9

Let the present age of Rehman be x years.

Case Ī

Age of Rehman before 3 years = (x - 3) yrs

Case ĪĪ

Age of Rehman after 5 years = (x + 5) yrs

With the situation of this query, we have,

 \implies \tt \frac{1}{x - 3}  +  \frac{1}{x + 5}  =  \frac{1}{3}  \\ \\   \implies \tt  \frac{x + 5 + x  -  3 }{( x- 3)(x + 5)}  =  \frac{1}{3}  \\  \\ \implies \tt \frac{2x + 2}{ {x}^{2} + 2x - 15 }  =  \frac{1}{3}  \\   \tiny{ \text{performing \: cross - multiplication}}\\ \implies \tt 6x + 6 = x^{2} + 2x - 15 \\  \tiny{ \text{switching \: the \: sides}}\\ \implies \tt x^{2} + 2x - 15 = 6x + 6 \\ \tiny{ \text{transposing \: RHS \: to \: LHS}} \\ \implies \tt {x}^{2}  + 2x - 6x - 15 - 6 = 0 \\  \\ \implies \tt {x}^{2}  - 4x - 21 = 0 \\ \tiny{ \text{applying \: completing \: the \:square \: method }} \\ \implies \tt {(x)}^{2}  - 2(x)(2) +  {(2)}^{2}   -  {(2)}^{2} - 21 = 0 \\  \\ \implies \tt {(x - 2)}^{2}  - 4 - 21 = 0 \\  \\ \implies \tt {(x - 2)}^{2}  - 25 = 0 \\  \\ \implies \tt {(x - 2)}^{2} = 25 \\ \tiny{ \text{taking \: square \: roots \: of \: both \: side}} \\ \implies \tt \sqrt{ {(x - 2)}^{2} } =   \sqrt{25}  \\  \\ \implies \tt(x - 2) =  \pm5 \\

Now,

  • x = (5 + 2) = 7
  • x = (- 5 + 2) = - 3

Since, Ages can't be negative. Negative values are omitted.

Thus,

  • Present age of Rehman is 7 years.
Answered by ItzMeMukku
22

\large\bf{\underline{\underline{Let \:us\: say}}}

\textbf\color{red}{present age of Rahman is x years.}

\large\bf{\underline{\underline{Three\: years \:ago,}}}

\textbf\color{red}{Rehman’s age was (x – 3) years.}

\large\bf{\underline{\underline{Five\: years \:after,}}}

\textbf\color{red}{his age will be (x + 5) years}

\large\bf{\underline{\underline{Given}}}

The sum of the reciprocals of Rehman’s ages 3 years ago and after 5 years is equal to 1/3.

\sf{1/x-3 + 1/x-5 = 1/3}

\sf{(x+5+x-3)/(x-3)(x+5) = 1/3}

\sf{(2x+2)/(x-3)(x+5) = 1/3}

\sf{3(2x + 2) = (x-3)(x+5)}

\sf{6x + 6 = x2 + 2x – 15}

➦b\sf{x2 – 4x – 21 = 0}

\sf{x2 – 7x + 3x – 21 = 0}

\sf{x(x – 7) + 3(x – 7) = 0}

\sf{(x – 7)(x + 3) = 0}

\underline{\boxed{\sf\purple{x\: =\: 7, -3}}}

\underline{\bf{As\: we\: know, \:age \:cannot\: be\: negative.}}

\underline{\bf{Therefore, \:Rahman’s \:present \:age \:is \:7\: years.}}

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Thankyou :)

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