The sum of the reciprocals of Renman's age, (in years),3 years ago and 5 years from now is 1/3 .Find their present ages.
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Answer:
Let his present age be x years.
3 years ago his age was x-3 years.
5 years from now is age will be x+5 years.
sum of Reciprocal of these will be 1/3
so,
1/(x-3) + 1/(x+5) = 1/3
((x+5) + (x-3))/((x-3)*(x+5)) = 1/3
Cross Multiplication
3x+15+3x-9 = (x-3)*(x+5)
6x + 6 = x^2 + 5x - 3x - 15
x^2 +2x - 15 - 6 - 6x = 0
x^2 - 4x - 21 = 0
x^2 -7x + 3x - 21 = 0
x(x-7)+3(x-7) = 0
(x+3)(x-7)=0
x = -3(ignore)
x = 7
Explanation:
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My self krinna Anandpara
from Ahmedabad
CALSS 10 ICSE
and yes sure I will
u also be safe
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