the sum of the reciprocals of two consecutive odd number natural numbers is 12 / 35 . Find those numbers .
.
.THE FIRST ONE TO ANSWER CORRECT WILL BE MARKED AS BRAINLIST
Answers
Answered by
1
Let n and n+2 be the integers.
Then, 1/n + 1/(n+2) = 12/35
Multiply by the LCD, 35n(n+2) to get: 35(n+2) + 35n = 12n(n+2)
70n + 70 = 12n2+ 24n
12n2 - 46n - 70 = 0
6n2 - 23n - 35 = 0
(6n + 7)(n - 5) = 0
n = -7/6 or 5
-7/6 is not an integer, so n = 5
The integers are 5 and 7.
Then, 1/n + 1/(n+2) = 12/35
Multiply by the LCD, 35n(n+2) to get: 35(n+2) + 35n = 12n(n+2)
70n + 70 = 12n2+ 24n
12n2 - 46n - 70 = 0
6n2 - 23n - 35 = 0
(6n + 7)(n - 5) = 0
n = -7/6 or 5
-7/6 is not an integer, so n = 5
The integers are 5 and 7.
aditya2019:
pls mark as brainliest
Answered by
0
let the consecutive odd numbers be x and x+2
thus, 1/x +1/x+2 =12/35
by solving this we get x=5,7
thus, 1/x +1/x+2 =12/35
by solving this we get x=5,7
Similar questions