The sum of the remainders obtained by when {x^3+(k+8)} is devided by (x+1) or when it is devided by (x+1) is zero .
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Step-by-step explanation:
Question:-
the sim of the remainder obtained by when {x³+(k+8)}
is divided by (x+1) or when it is divided by (x +1) is zero
solution:-
according to questions
x+1=0
x= -1
the put the value of x in given equation:-
{(-1)³+(k+8)}=0
{-1 +k + 8}=0
k+ 7=0
k= -7
Answer:- k= -7
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