Question

The sum of the remainders obtained when (+ (k+8)x + k) is divided by (x - 2)
or when it is divided by (x + 1) is zero. Find the value of k.​

Answer 1

Answer:

3

+(k+8)x+k

Put x=2 to obtain first remainder

⇒R

1

=(2)

3

+(k+8)

2

+k=24+3k

Put x=−1 to obtain second remainder

⇒R

2

=(−1)

3

+(k+8)+k=−9

So R

1

+R

2

=0

⇒24+3k−9=0

⇒3k=−15

⇒k=−5.