Math, asked by Vyom4598, 1 year ago

The sum of the remainders obtained when x3+(k+8)x+k is divided by x-2 and when it is divided by x-1 is 0. find the value of k

Answers

Answered by Anonymous
7
x = 2
2^3 +(k+8)*2 + k = 8+16+3k = 24 + 3k
x = 1
1 + (k+8) + k = 9 + 2k
Hence remainders are: 24+3k , 9+2k
Given: 24+3k+9+2k = 0 
33+5k = 0
33 = -5k
k = -33/5 or -6.6
Hope it helps.

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