Question

the sum of the remainders obtained when(xka square+(k+8)x+k)is divided by (x-2) or whenit is divided by (x +1)is 0. find k​

Answer 1

Step-by-step explanation:

((xk)2+(k+8)x+k)

x-2=0

x=2

in the place of X substitute 2

so it will be

((2k)2+(k+8)2+k)

4ksquare+2k+16+k=0

4k square +2k+k+16=0

4K square +3K=16-----1equation

X + 1 equal to 0

x=-1

(2ksquare)-1+(k+8)-1+k

-2ksquare-k-8+k=0

-2ksquare=8-----------2equation

4k^2+3k=16. *-2

-2k^2+0=8. *4

-8k^2-6k=-32

-8k^2+0=32

(+)

8 k the whole square gets cancelled

-6k=-32-32

-*-=+

hence here

-6k=64

k=64/-6

10.666

-10.67 answer