Math, asked by amruthdeep5091, 17 days ago

The sum of the remainders of 125÷4, 234÷5 and 345÷2 is __________ *
1 point
4
16
18
6

Answers

Answered by zaramujibmmx

0

Answer:

1+4+1=6

when 125 / 4 remainder is 1 as 4*31=124

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