the sum of the roots of equation x^2-8x+2=0
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Answered by
28
Heya!
Here is yr answer......
I think the ques is ----
=> x² - 2x - 8= 0
=> x² - 2x + 4x - 8 = 0
=> x(x-2) + 4(x-2) = 0
=> (x+4) (x-2) = 0
x+4 = 0 => x = -4
x-2 = 0 => x = 2
Sum of the zeros = -4+2 = -2
Hope it hlpz..
Here is yr answer......
I think the ques is ----
=> x² - 2x - 8= 0
=> x² - 2x + 4x - 8 = 0
=> x(x-2) + 4(x-2) = 0
=> (x+4) (x-2) = 0
x+4 = 0 => x = -4
x-2 = 0 => x = 2
Sum of the zeros = -4+2 = -2
Hope it hlpz..
Dhinowilliams:
No..I think you have to check the question carefully..
The equation you given in the answer is wrong
Yes question is Right
No..I'm telling the equation in the question is correct. But the equation in the answer is wrong
solve it to use sridhrachaya formula
What??
Answered by
36
Given Quadratic equation is x^2 - 8x + 2 = 0
= > On comparing with ax^2 + bx + c = 0, we get a = 1, b = -8, c = 2.
We know that sum of the roots = -b/a
= -(-8)/1
= 8.
Hope this helps!
= > On comparing with ax^2 + bx + c = 0, we get a = 1, b = -8, c = 2.
We know that sum of the roots = -b/a
= -(-8)/1
= 8.
Hope this helps!
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