Question

the sum of the roots of one of the following equation is 3 which one is the equation​

Answer 1

The required optio (2) is correct.

Step-by-step explanation:

The quadratic equation is defined as

$ax^{2} +bx+c=0$

Then, the sum of its roots = $\dfrac{-b}{a}$

Check options:

In option 1:

The given equation is

$2x^{2} -3x+9=0$

The sum of its roots =  $\dfrac{-(-3)}{2}=\dfrac{3}{2}$ ≠ 3

In option 2:

The given equation is

$-x^{2} +3x-3=0$

The sum of its roots $=\dfrac{-3}{-1}=3=3$ , is the correct.

In option 3:

The given equation is:

$3x^{2} -3x+3=0$

The sum of its roots $=\dfrac{-(-3)}{3}=1\neq 3$

Hence, the required optio (2) is correct.

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