Question

the sum of the roots of the equation 3x^2-7x+11=0 is​

Answer 1

Answer:

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

3

2

−

7

+

1

1

=

0

3x^{2}-7x+11=0

3x2−7x+11=0

=

3

a={\color{#c92786}{3}}

a=3

=

−

7

b={\color{#e8710a}{-7}}

b=−7

=

1

1

c={\color{#129eaf}{11}}

c=11

=

−

(

−

7

)

±

(

−

7

)

2

−

4

⋅

3

⋅

1

1

√

2

⋅

3

x=\frac{-({\color{#e8710a}{-7}}) \pm \sqrt{({\color{#e8710a}{-7}})^{2}-4 \cdot {\color{#c92786}{3}} \cdot {\color{#129eaf}{11}}}}{2 \cdot {\color{#c92786}{3}}}

x=2⋅3−(−7)±(−7)2−4⋅3⋅11

Answer 2

Answer:

3x^2-7x+11

Step-by-step explanation:

3x^2-11x+3x+11

x(3x+11) 1(3x+11)

3x+11=0

(x= -11/3).... x+1=(x= -1)