Question

The sum of the roots of the equation -x² + 3 x -3=0 is
A) 3
B) 3/4
C) -3
D) 1

Answer 1

GIVEN :-

• A quadratic equation = x² + 3x - 3 = 0.

TO FIND :-

• The sum of roots ( ɑ + β )

SOLUTION :-

★ If the polynomial is x² + 3x - 3 = 0.

➠ x² + 3x - 3 = 0

As we know that,

➠ ɑ + β = -cofficient of x/cofficient of x²

➠ ɑ + β = -b/a

➠ ɑ + β = -3/1

➠ ɑ + β = -3

Hence the sum of the roots of the equation x² + 3x - 3 = 0 is -3.

★ If the polynomial is -x² + 3x - 3 = 0.

➠ -x² + 3x - 3 = 0

As we know that,

➠ ɑ + β = -cofficient of x/cofficient of x²

➠ ɑ + β = -b/a

➠ ɑ + β = -3/-1

➠ ɑ + β = 3

Hence the sum of the roots of the equation -x² + 3x - 3 = 0 is 3.

★═══════════════════★

➳ ɑ + β = -cofficient of x/cofficient of x²

➳ ɑ × β = constant term/cofficient of x².

➳ quadratic formula = [ { -b ± √( b² - 4ac ) }/2a ]

➳ quadratic equation = x² - (ɑ + β)x + (ɑβ) = 0

Answer 2

$\large{\underline{\sf{\orange{Given-}}}}$

• Quadratic Equation -$-x² + 3 x -3=0$

$\large{\underline{\sf{\pink{To \: Find-}}}}$

• The sum of roots ( ɑ + β )

$\large{\underline{\sf{\purple{Solution-}}}}$

$:\implies\sf\alpha + β = -cofficient of x/cofficient of x²$

$:\implies\sf\alpha+ β = -b/a$

$:\implies\sf\alpha+ β = -3/1$

 $:\implies\sf\alpha+ β = -3$

Hence the sum of the roots of the equation x² + 3x - 3 = 0 is -3.