The sum of the saleries of A and B Rs.2200 the ratio in their salaries is 9:11. how much reduction is done from each so that the ratio in their salaries be 2:3?
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The answer is 770 from A and 880 from B.
Step by step: Let the ratio be x
Given ratio = 9x:11x
Total amount =2200
Total ratio=20x
=>20x=2200
=>x=2200/20=110
Therefore x =110
Salaries = 9x:11x = 9(110):11(110) = 990:1210
2x:3x = 2(110):3(110) = 220:330
=> The amount to be subtracted is (A-220),(B-330) =770,880
Step by step: Let the ratio be x
Given ratio = 9x:11x
Total amount =2200
Total ratio=20x
=>20x=2200
=>x=2200/20=110
Therefore x =110
Salaries = 9x:11x = 9(110):11(110) = 990:1210
2x:3x = 2(110):3(110) = 220:330
=> The amount to be subtracted is (A-220),(B-330) =770,880
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