Question

the sum of the series 1/√3+1+3/√3 ... to 18 terms is​

Answer 1

Answer:

Ello user

The first term is ... 1/√3

Common ratio is ... √3

Sum is required upto 18 terms

So,

S = a(r^n -1)/r-1

S = 1/√3(√3^18 - 1)/√3-1

S = (3^9 - 1)/3 - √3

On rationalising , we get

S = (3^9 - 1)(3 + √3)/6

S = (3^10 + 3^19/2 - 3 -√3)/6.

Hope this helps.

_________________+_____________________

Step-by-step explanation: