the sum of the series 1+3+5+7+...up to 10 terms is
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Answered by
1
here
given series are in AP
I.e 1+3+5+7+...
d=2
a=1
n=10
s=n/2(2a+(n-1)d)
=10/2(2.1+(10-1)2
=5(20)
=100 ans
given series are in AP
I.e 1+3+5+7+...
d=2
a=1
n=10
s=n/2(2a+(n-1)d)
=10/2(2.1+(10-1)2
=5(20)
=100 ans
Answered by
1
Hey there!!
This is problem of AP..
• 1+3+5+7........ Upto 10 terms
Here, a = 1, d = 2
Now use formula, Sn = n/2(2a +(n-1)d)
Here, n = 10 terms
Now,> Sn = 10/2 {2 + (10 - 1)×2}
>> = 5×20
>>>>>>> Sn = 100
<------------------------------------------------------------------------>
Hope it will help u
This is problem of AP..
• 1+3+5+7........ Upto 10 terms
Here, a = 1, d = 2
Now use formula, Sn = n/2(2a +(n-1)d)
Here, n = 10 terms
Now,> Sn = 10/2 {2 + (10 - 1)×2}
>> = 5×20
>>>>>>> Sn = 100
<------------------------------------------------------------------------>
Hope it will help u
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