Question

the sum of the shares of x,y and z is Rs.936. if 3x= 4y = 6z, find the shares of x,y and z​

Answer 1

Answer:

Given, (3x – 4y): (2x – 3y) = (5x – 6y): (4x – 5y)

This can be rewritten as

2x−3y

3x−4y

=

4x−5y

5x−6y

3x−4y−2x−3y

3x−4y+2x−3y

=

5x−6y−4x−5y

5x−6y+4x−5y

x−y

5x−7y

=

x−y

9x−11y

5x – 7y = 9x – 11y

4y = 4x

x/y = 1/1

Thus,

x: y = 1: 1