The sum of the speed of a boat in still water and the speed of the current is 10 kmph. If the boat takes 40 % of the time to travel downstream when compared to that of upstream, then find the difference of the speeds of the boat when travelling downstream and upstream
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Answered by
26
LET SPEED OF BOAT N STILL WATER BE X KMPH
SO SPEED OF CURRENT IS (10-X) KMPH
WE KNOW DISTANCE = SPEED * TIME
SO (X-(10-X))*T=(X+(10-X))*40T/100
2X-10=4 OR X=7
DIFFERENCE=(X+(10-X))+(X-(10-X))=10+2X-10=2*7=14 KMPH
SO SPEED OF CURRENT IS (10-X) KMPH
WE KNOW DISTANCE = SPEED * TIME
SO (X-(10-X))*T=(X+(10-X))*40T/100
2X-10=4 OR X=7
DIFFERENCE=(X+(10-X))+(X-(10-X))=10+2X-10=2*7=14 KMPH
Answered by
4
Answer:
6 kmph is the answer
Step-by-step explanation:
Reqd difference = downstream speed - upstream speed
= (10-4) kmph
= 6kmph
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