the sum of the sq.of two consecutive odd positive integer is 394. find the integers
Answers
Answered by
1
let the ingers x and x+2
so
2xsq.+4+4x=394
xsq. + 2 + 2x = 192
now solve this..
hope it helps you.
so
2xsq.+4+4x=394
xsq. + 2 + 2x = 192
now solve this..
hope it helps you.
barbie227:
i did same earlier but ... answer??
Answered by
1
Question;-
the sum of the sq.of two consecutive odd positive integer is 394. find the integers
Method of solution;-
let to be first consecutive odd positive(2x+1) and second consecutive odd positive(2x+3)
According to the question;-
(2x+1)²+(2x+3)²=394
4x²+1+4x+4x²+9+12x=394
8x²+16x-384=0
x²+2x-48=0
x²+8x-6x-48=0
x(x+8)-6(x+8)=0
(x+8)(x-6)=0
x=-8 x=6
Again, Hence,
x1=2(6)+1=13
x2=2(6)+3=15
Conclusion ;- 13 and 15 are required consecutive odd Integers.
Thanks!!
the sum of the sq.of two consecutive odd positive integer is 394. find the integers
Method of solution;-
let to be first consecutive odd positive(2x+1) and second consecutive odd positive(2x+3)
According to the question;-
(2x+1)²+(2x+3)²=394
4x²+1+4x+4x²+9+12x=394
8x²+16x-384=0
x²+2x-48=0
x²+8x-6x-48=0
x(x+8)-6(x+8)=0
(x+8)(x-6)=0
x=-8 x=6
Again, Hence,
x1=2(6)+1=13
x2=2(6)+3=15
Conclusion ;- 13 and 15 are required consecutive odd Integers.
Thanks!!
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