Question

the sum of the square are concutive natural number 313 Identity (a+b)^2​

Answer 1

$\sf{\underline\blue{Answer:-}}$

Given: sum of the squares of two consecutive natural numbers is 313

To find the numbers

Sol: Let 1 number be x. Since the numbers are consecutive, the other number would be x+1.

Square both and add together to equal 313.

x

2

+(x+1)

2

=313

x

2

+x

2

+2x+1=313

2x

2

+2x−312=0

x

2

+x−156=0

(x−12)(x+13)=0

x=12,x=−13

given numbers are natural . so x=12 and x+1=13 are the two numbers.

Answer 2

$x=12\\and\\x=-13$

see the pic that i have attached

hope this helps...